Two vehicles are approaching an intersection. One is a 2300 kg pickup traveling at 15.0 m/s from east to west (the -x- direction), and the other is a 1600 kg sedan going from south to north (the +y- direction at 25.0 m/s).
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Momentum (p) is given by the formula: p = mv where m is the mass of the object and v is its velocity. For the pickup: m1 = 2300 kg v1 = -15.0 m/s (negative because it's going from east to west) p1 = m1 * v1 p1 = 2300 kg * -15.0 m/s For the sedan: m2 = 1600 Show more…
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Two vehicles are approaching an intersection. One is a $2300 \mathrm{~kg}$ pickup traveling at $14.0 \mathrm{~m} / \mathrm{s}$ from east to west (the $-x$ -direction), and the other is a $1600 \mathrm{~kg}$ sedan going from south to north (the $+y$ -direction) at $24.0 \mathrm{~m} / \mathrm{s}$. (a) Find the $x$ - and $y$ -components of the net momentum of this system. (b) What are the magnitude and direction of the net momentum?
Two vehicles are approaching an intersection. One is a $2500 \mathrm{~kg}$ pickup truveling at $14.0 \mathrm{~m} / \mathrm{s}$ from cast to west (the $-x$ -direction). and the other is a $1500 \mathrm{~kg}$ sedan going from south to north (the $+y$ -direction) at $23.0 \mathrm{~m} / \mathrm{s}$. (a) Find the $x$ - und $y$ -components of the net momentum of this system. (b) What are the magnitude and direction of the net motnentum?
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