00:01
Hi everyone here two water jet from the tank collides and form a humogenous jet.
00:07
We have to find its speed angle and loss of fluid particles.
00:25
Let us share the solution.
00:27
Calculating the force acting along x -axis summation of fx must be zero.
00:37
So you will get minus v2, row a2, into b2, 2 plus v3, row a3, v3, coss of theta must be 0.
00:55
So it can be written as minus v2 square a 2 plus v3 square a3, a 3, cos of theta is equal to 0.
01:07
Say first equation of force along y -axis must be 0.
01:12
So it will be minus v1 row a1 into b1 plus b3 row a3 v3 sign of theta must be 0 so you can write minus b1 is square a 1 plus b3 square a 3 sine of theta is equal to 0 second equation from first equation you can find b3 and b3 will be b2 square into a2 square upon a3 cost theta.
02:01
Not it is a square, it is a2.
02:13
And from equation 2 and 3 minus b1 square row a1 b1 square b1 square a1 plus b3 square that is v2 square a 3 sine of theta into a 3 just a moment b2 square a 2 upon a 3 cos of theta into a 3 sign of theta must be equal to 0 so from here you will get 10 of theta to be equal to v1 square upon b2 square into a 1 upon a 2 square into a 1 upon a 2 now a1 is pi d1 square by 4, that is d1 is 0 .1.
03:45
So it is to be 0 .00785 meter square.
03:52
A2 will be pi d2 square by 4, that is pi into 0 .12 square upon 4.
04:01
So it is equal to 0 .01 meter square.
04:10
The values in equation 4 so 10 of theta b1 is given 4 upon 6 in the problem this is given a 1 upon a 2 a 1 is 0 00785 upon 0 .01 so it is to be 0 .34 hence theta is equal to 18 .77 degree this is the one of the answer now b required b3 now applying conservation of mars you will get minus row b1 into a1 minus row b2 into a2 plus row b2 into a3 is equal to 0 so from here you will get b3 a3 a3 is called to 0 so from here you will get b3 a3 is called to b1 a 1 plus b2 a 2 so from here from first equation we can write minus b2 a2 2 square a 2 plus v3 square cos of theta into a 3 is equal to 0 so by combining equation 5 and 6 we can get v3 is called to v2 square a 2 divided by cost of theta b1 a1 plus b2 a2 so b3 you may write b2 squared into a 2 divided by cos of theta into b1 a 1 plus b2 a 2 now substituting the value b2 is 6 a 2 is 0 .01 cause of 18 point 7 7 7 b1 is 4 into 0 0.
07:25
1 square 0 .0087 plus 6 into 0 .01...