Question

Question 1 (1 point) A small glass bead has been charged to 1.9 nC. What is the strength of the electric field 2.0 cm from the center of the bead? ($k = \frac{1}{4\pi\epsilon_0} = 8.99 \times 10^9 \text{ N} \cdot \text{m}^2/\text{C}^2$) a) $8.5 \times 10^{-7} \text{ N/C}$ b) $8.1 \times 10^{-5} \text{ N/C}$ c) $4.3 \times 10^4 \text{ N/C}$ d) $8.5 \times 10^2 \text{ N/C}$ e) $4.5 \times 10^{-7} \text{ N/C}$ f) $6.1 \times 10^{-5} \text{ N/C}$

          Question 1 (1 point)
A small glass bead has been charged to 1.9 nC. What is the strength of the electric field 2.0 cm
from the center of the bead? ($k = \frac{1}{4\pi\epsilon_0} = 8.99 \times 10^9 \text{ N} \cdot \text{m}^2/\text{C}^2$)
a) $8.5 \times 10^{-7} \text{ N/C}$
b) $8.1 \times 10^{-5} \text{ N/C}$
c) $4.3 \times 10^4 \text{ N/C}$
d) $8.5 \times 10^2 \text{ N/C}$
e) $4.5 \times 10^{-7} \text{ N/C}$
f) $6.1 \times 10^{-5} \text{ N/C}$

Question 1 (1 point)
A small glass bead has been charged to 1.9 nC. What is the strength of the electric field 2.0 cm
from the center of the bead? (k = (1)/(4πϵ0) = 8.99 × 10^9 N·m^2/C^2)
a) 8.5 × 10^-7 N/C
b) 8.1 × 10^-5 N/C
c) 4.3 × 10^4 N/C
d) 8.5 × 10^2 N/C
e) 4.5 × 10^-7 N/C
f) 6.1 × 10^-5 N/C

Added by Connie W.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Krystal K

03/14/2023

Step 1

99x10^9 Nm^2/C^2), |q| is the magnitude of the charge, and r is the distance from the center of the bead. Show more…

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ty Question 1(1point) A small glass bead has been charged to 1.9 nC.What is the strength of the electric field 2.0 cm from the center of the bead?(k=1/4TTe0=8.99x109Nm2/C2 a8.510-7N/C b8.1x10-5N/C c4.3x104N/C d8.5x102N/C e4.5x10-7N/C f6.110-5N/C