00:01
Hello, so in this question, wavelength of a cell phone transmission is given and we need to find the frequency, its energy in kilojoules and in moles.
00:12
Okay, so first we'll find the frequency using the equation for wavelength that is lambda is equal to c by f where f is the frequency so f will be equal to c upon lambda that is three times 10 to power 8 divided by wavelength is given as 3 .048 multiplied by 10 to power 8 nanometers.
00:41
So if we convert it into meters then it will be 0 .3048.
00:46
So after solving this, our final answer will be equal to 9 .84 times 10 to power 8 meter inverse.
00:59
So this will be the frequency.
01:01
Frequency for the transmission now it is asking to find the energy so energy will be equal to h f where h is the blanks constant that is 6 .626 times 10 is to power minus 34 times frequency is 9 .84 times 10 is to power 8 so after solving this our final answer will be 6 .52 times 10 to power minus 25 in joules.
01:37
So now if we convert it into kilojoules then it will be 6 .5 2 times 10 to power minus 22 kilojoules.
01:46
Okay that is simply by multiplying with thousand...