00:01
The empirical formula.
00:02
So number seven, so it's just calculated the empirical formula will compound nicotine, 67 .9 % carbon, 5 .7 % hydrogen, and 26 .4 % nitrogen.
00:13
So you do 27 .9 grams, you convert to the percentage mean pure 100 grams.
00:23
So it's going to be 67 .9 grams of carbon.
00:29
5 .7 grams of hydrogen.
00:34
And 26 .4 grams of nitrogen.
00:40
You divide by the molar mass of each of them, so 12, 1 .01, 14, you can get how many bowls are in it.
00:54
So you have, let me see, 5 .6, 5 .6, and then 1 .8.
01:04
So then you have c, 4 .8.
01:09
5 .6, 8, 5 .6, 0, 1 .8.
01:16
You divide by the least, the number, at least, most by each one of the element, giving you c3, h3, and, oops, not o, that's supposed to be in it...