'uniform electric field of magnitude 382 N/C pointing in the positive x-direction acts on an electron_ which is initially at rest: The electron has moved 2.60 cm (a) What is the work done by the field on the electron? What is the change in potential energy associated with the electron? (c) What is the velocity of the electron? magnitude m/s direction Select ='
Added by Donna M.
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Given that the charge of an electron is \(1.6 \times 10^{-19}\) C and the change in potential energy is -15.912 x 10^-21 J, we can calculate the work done as follows: \[ W = (1.6 \times 10^{-19} C) \times (-15.912 \times 10^{-21} J) \] Show more…
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