00:01
Now in this question the value of the edge is given which is equal to 0 .610 meter then the b is given this will be 0 .305 meter and the length l is equal to 2 .44 meter here the value of temperature i is taken as 21 .1 degrees celsius then o is taken as 26 .7 degrees celsius, then the mass rate is given, which is equal to 2 .72 kilogram per hour.
00:44
We will convert into the second, so this will be 7 .556, 10 -2 -4 kilogram per second.
00:55
For the air at the mean temperature, this will be equal to 21 .1 plus 26 .7 divided by 2.
01:09
This will be equal to 23 .9 degrees celsius.
01:14
Now, the value of the density, this will be equal to 1 .1 -8 kilogram per meter cube.
01:27
The value of cp which will be equal to 1 .007 joules per kilogram per kelvin then the value of the constant k which is 0 .0543 watt per meter per kelvin the value of mu is equal to the 1 .840 4 multiplied by 10 to minus 5 kilogram per meter per second and the value of pr this will be equal to 0 .7298 by this we can find the perimeter p which will be equal to 2 height plus width this will be equal to 1 .1 .83 meter.
02:32
Then the cross -sectional area is this will be h multiply by b.
02:39
So this will be equal to 0 .18605 meter square.
02:47
Then the surface area, this is cross -sectional area...