UPLOAD YOUR ANSWER A motorcycle starts from rest at \( \mathbf{t}=\mathbf{0} \) and travels along a straight road with a constant acceleration of \( 6 \mathrm{ft} / \mathrm{s}^{2} \) until it reaches a speed of \( 50 \mathrm{ft} / \mathrm{s} \). Afterwards it maintains this speed. Also, when \( \mathbf{t}=\mathbf{0} \), a car located 6000 ft down the road is traveling toward the motorcycle at a constant speed of \( 30 \mathrm{ft} / \mathrm{s} \) Determine the time and the distance traveled by the motorcycle when they pass each other. Upload Choose a File
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- Use the formula \( v = u + at \), where \( v = 50 \, \text{ft/s} \), \( u = 0 \, \text{ft/s} \), and \( a = 6 \, \text{ft/s}^2 \). - Solve for \( t \): \[ 50 = 0 + 6t \implies t = \frac{50}{6} \approx 8.33 \, \text{s} \] Show more…
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