00:01
Hello student, in the given question, we use appendix table 3 to find out the probabilities for the standard normal random variable z.
00:47
So, first probability we have to find is probability of z which is greater than 1 .45 which is equals to 1 minus probability of z is less than 1 .45 which is equals to 1 minus this probability is 0 .9265 which is equals to 0 .0735.
01:16
Now the second probability, probability b to find out option b probability is z is less than minus 1 .75 which is equals to 0 .0401.
01:32
Now the c part, the probability for 0 .97 which is less than or equals to z which is less than or equals to 2 .41 which is equals to probability of z is less than or equals to 2 .41 minus probability of z is less than 0 .97 which is equals to 0 .9918 minus 0 .8365 equals to 0 .1553.
02:22
Now in d part, we have to find out the probability of minus 1 .68 is less than or equals to z is less than or equals to 0 .57 which is equals to the probability of z is less than minus 0 .57 minus probability of z is less than minus 1 .68 which is equals to probability of z less than 0 .17 is equals to 0 .2852 minus 0 .0461 which is equals to 0 .2391.
03:16
Now for part e, the probability of z is greater than or equals to 0 which is equals to 0 .500.
03:26
Now in part f, we have to find the probability for minus 2 .13 is less than or equals to z is less than or equals to 1 .11 which is equals to probability of z is less than or equals to 1 .11 minus probability of z is less than minus 2 .13 which is equals to 0 .8665 minus 0 .0162 which is equals to 0 .8503...