00:01
So we have a few systems to solve.
00:02
The first one is x equals y squared plus 4y minus 5 and x equals 0.
00:13
So i'm just going to set my y squared plus 4y minus 5 equal to 0.
00:19
I'm going to factor that.
00:22
I have y plus 5 and y minus 1.
00:25
So i have two values for y, negative 5, and positive 1.
00:34
So that means that i have two solutions, 0 negative 5 and 01.
00:43
So you want to pick, looks like choice c for that one.
00:53
Now in my next problem, i have y equals x squared plus 7 and y equals 4x plus 3.
01:08
Okay, so i'm going to set these two equal to each other.
01:15
Since it's quadratic, i'm going to move everything to one side.
01:21
So that gives me x squared minus 4x plus 4 equals 0.
01:30
That gives me x minus 2 times x minus 2 equals 0.
01:36
So i get one value, which is 2.
01:39
I'm going to plug that in...