00:01
Hello students here we have to find the limits.
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First one, it is given that limit x tends to 1, x cubed minus a divided by x minus 2.
00:16
This can be written as limit x which tends to 1 in the form of a cube minus b cube, a minus b means x minus 2 into a square plus b square plus b square plus 2 square plus 2 into 2 x divided by this will be x minus 2.
00:36
So upon solving this is 1 plus 4 plus 2 that is equal to 7.
00:43
And therefore we can say that limit of x which tends to 1, x cube minus 8 divided by x minus 2 is equal to 7.
00:56
Then next we have b question that is limit of.
01:02
X which tends to minus 4 x squared plus 6x plus 8 divided by, this will be x square plus 2x minus 8.
01:13
That means this can be written as limit x tends to minus 4.
01:19
It will be x plus 4 into x plus 2 divided by x plus 4 into x minus 4 which is equal to minus 4, 2 by minus 6 which is 1 by 3.
01:35
And therefore we can say that the limit of x which tends to minus 4 of x squared plus 6x plus 8 divided by x squared plus 2x plus 8 will be equal to 1 divided by 3.
01:54
Further now in the c part we are given that the limit of x which tends to 1 .2 .0 .4 .5 .4 .0 .5 .0 .1...