Use Hess's Law to calculate the enthalpy change for the reaction WO3(s) + 3H2(g) --> W(s) + 3H2O(g) from the following data: 2W(s) + 3O2(g) --> 2WO3(s) ΔH = -1685.4 kJ 2H2(g) + O2(g) --> 2H2O(g) ΔH = -477.84 kJ
Added by David P.
Step 1
Reaction 1: 2W(s) + 3O2(g) → 2WO3(s) ΔH1 = -1685.4 kJ Reaction 2: 2H2(g) + O2(g) → 2H2O(g) ΔH2 = -477.84 kJ Show more…
Show all steps
Your feedback will help us improve your experience
David Collins and 78 other Chemistry 101 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Consider the following reactions: 2C2H4O(l) + 2H2O(l) → 2C2H6O(l) + O2(g) ΔH = 715.6 kJ 2CO2(g) + 2H2O(g) → C2H4O(l) + O2(g) ΔH = 2042.2 kJ Calculate the enthalpy change for the reaction: C2H6O(l) + 3O2(g) → 2CO2(g) + 3H2O(l)
Aparna S.
Use Hess's Law to calculate the enthalpy change for the reaction from the following data: -1685.4 kJ -477.84 kJ
Susan H.
Consider the two reactions. 2NH3(g)+3N2O(g)4NH3(g)+3O2(g)⟶4N2(g)+3H2O(l)⟶2N2(g)+6H2O(l) Δ𝐻∘=−1010 kJΔ𝐻∘=1531 kJ Using these two reactions, calculate and enter the enthalpy change for the reaction below. N2(g)+12O2(g)⟶N2O(g)
David C.
Recommended Textbooks
Chemistry: Structure and Properties
Chemistry The Central Science
Chemistry
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD