Use information from the table below to calculate the Gibbs free energy yields of aerobic respiration of glucose (C6H12O6) according to reaction 1 and acetate (CH3COO-) according to reaction 2, under standard state conditions. Note that the G°f for H+ can be calculated from the table based on -5.69 per pH unit, which we will assume is 7.0 (for -39.83 kJ/mol) unless otherwise specified, since this is a common pH in natural environments. Show calculations.
C6H12O6 + 6O2 → 6CO2 + 6H2O (1)
CH3COO- + H+ + 2O2 → 2CO2 + 2H2O (2)
Based on the information above, which metabolism yields more free energy per mol of O2 consumed? Which metabolism would be favored assuming equal availability of glucose and acetate?