00:01
In this problem we need to solve the system of equations by gaussian elimination.
00:07
So let us first make the matrix.
00:11
So our matrix will be first we write the coefficients of x, y and z in first three columns.
00:20
So 1, 1, 1, 1, 1, 2, 2, 2, 3 and then in the last column we write the concept.
00:32
Terms 3, 4 and 7.
00:37
Now to solve the system we need to get identity matrix in first three columns.
00:45
So let us first try to get a 1 here.
00:51
So we can do r3 is r3 minus r2.
00:59
So we have 1, 1, 1, 3, 1, 1, 2.
01:06
4 and then we have 2 minus 1 that is 1 then we have 2 minus 1 again here 3 minus 2 and here we have 7 minus 4 that is 1 1 and 3 so our new matrix now is 1 1 3 1 1 3 1 1 3 1 1 3 1 1 2, 4 and 1, 1113.
01:44
So now next step is, let us do r3 is r3 minus r1 and then r2 is r2 minus r1.
02:03
So we have 1111 3 and 1 minus 1 minus 1...