Use Kirchhoff's Laws to solve for the time constant to charge the capacitors in the circuit below. Use the directions of current shown in the diagram. The values for the resistors and capacitors labeled are as follows: C1= 0.48?F C2= 0.36?F R3= 8.8? R4= 4.4? c I I1 C1 + I3 R3 24 V a b I5 I2 I4 R4 C2 d
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Step 1: Apply Kirchhoff's current law at node A: I = I3 + I4 Show more…
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For one approach to problems like this one, consult Interactive Solution $\underline{20.99}$ at . Four identical capacitors are connected with a resistor in two different ways. When they are connected as in part $a$ of the drawing, the time constant to charge up this circuit is $0.72 \mathrm{~s}$. What is the time constant when they are connected with the same resistor as in part $b$ ?
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