Use Part I of the Fundamental Theorem of Calculus to find the derivative of [ F(x)=int_{x}^{1} sin left(t^{5} ight) d t ] [ F^{prime}(x)= ]
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In this case, our function f(t) is sin(t^5). However, our limits of integration are from x to 1, not from a constant to x. This means we need to use the property of integrals that the integral from a to b of f(t) dt is equal to the negative integral from b to a Show more…
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