00:01
Okay, so we have the a is 8 .0, 0, b is 8, 18, 18, 0 ,0, and c is 0 ,18, 0 ,0, and d is 0 .0, 0 .8.
00:16
We know that's ab.
00:18
The vector is this 0, 18, 0, 0, ad, that's equal to negative 8, comma, 0, 0 .8.
00:27
So we have that ab cross ad that's equal to ijk, 018, negative 8, 0 ,000, that gives me 144, comma 0, 1 .44.
00:54
Now for part p, we're given that s is equal to 1 over square root of 3, i plus 1 over square root of 3j, plus 1 over square root of 3k, you know our force is equal to 900 so we just multiply 900 times our s if we do that we get 300 square root of 3 i plus 300 square roots of 3 j and 300 square root of 3k now what's our force times without product of our ab cross a d well that's this equal to 1 4 4 times times 300 square root of 3 plus 144 times 300 square root of 3.
01:48
That gives me approximately 146949 .19 w.
01:55
Okay, now we're asked for part c to find the angle between the vectors.
02:01
Okay, so we know that sign of data.
02:03
Actually, i'm going to just name ab cross adn.
02:08
So sign of data is equal to magnitude of n cross s...