use scientific method 6 part question a survey of 1658 randomly selected adults showed that 564

a. The test is two-tailed because we are testing if the proportion is equal to 36%, not greater

Question

A survey of 1,658 randomly selected adults showed that 564 of them have heard of a new electronic reader. The accompanying technology display results from a test of the claim that 36% of adults have heard of the new electronic reader. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.05 significance level to complete parts (a) through (e). a. Is the test two-tailed, left-tailed, or right-tailed? a. is _ b. What is the test statistic? z = (Round to two decimal places as needed.) c. What is the P-value? P-value = ____ (Round to four decimal places as needed.) d. What is the null hypothesis and what do you conclude about it? Identify the null hypothesis. 1) H0: p < 0.36 2) H0: p ≠ 0.36 3) H0: p = 0.36 4) H0: p > 0.36 Choose the correct answer below. A. Fail to reject the null hypothesis because the P-value is greater than the significance level, alpha α. B. Reject the null hypothesis because the P-value is less than or equal to the significance level, alpha α. C. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, alpha α. D. Reject the null hypothesis because the P-value is greater than the significance level, alpha α. What is the final conclusion? A. There is not sufficient evidence to support the claim that 36% of adults have heard of the new electronic reader. B. There is sufficient evidence to support the claim that 36% of adults have heard of the new electronic reader. C. There is not sufficient evidence to warrant rejection of the claim that 36% of adults have heard of the new electronic reader. D. There is sufficient evidence to warrant rejection of the claim that 36% of adults have heard of the new electronic reader.

A survey of 1,658 randomly selected adults showed that 564 of them have heard of a new electronic reader. The accompanying technology display results from a test of the claim that 36% of adults have heard of the new electronic reader. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.05 significance level to complete parts (a) through (e).

a. Is the test two-tailed, left-tailed, or right-tailed? a. is _______

b. What is the test statistic? z = ______ (Round to two decimal places as needed.)

c. What is the P-value? P-value = ________ (Round to four decimal places as needed.)

d. What is the null hypothesis and what do you conclude about it? Identify the null hypothesis.

1) H0: p < 0.36
2) H0: p ≠ 0.36
3) H0: p = 0.36
4) H0: p > 0.36

Choose the correct answer below.

A. Fail to reject the null hypothesis because the P-value is greater than the significance level, alpha α.
B. Reject the null hypothesis because the P-value is less than or equal to the significance level, alpha α.
C. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, alpha α.
D. Reject the null hypothesis because the P-value is greater than the significance level, alpha α.

What is the final conclusion?

A. There is not sufficient evidence to support the claim that 36% of adults have heard of the new electronic reader.
B. There is sufficient evidence to support the claim that 36% of adults have heard of the new electronic reader.
C. There is not sufficient evidence to warrant rejection of the claim that 36% of adults have heard of the new electronic reader.
D. There is sufficient evidence to warrant rejection of the claim that 36% of adults have heard of the new electronic reader.

Added by Janet M.

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