Use standard reduction potentials to calculate the standard free energy change in kJ for the reaction: Pb²+ (aq) + 2Cu+ (aq) → Pb(s) + 2Cu²+ (aq) Pb²+ (aq) + 2e → Pb(s) E°= -0.126 V red Cu²+ (aq) + e → Cu+ (aq) E°= 0.153 V red ΔG° = kJ K for this reaction would be Submit Answer Retry Entire Group = than one. 8 more group attempts remaining