00:01
Hi, in this question we have to use superposition to solve for i0 and v0 in the given circuit.
00:08
So here if we see that 20 ohm, 80 ohm and 25 ohm all three are in the series.
00:18
Therefore if we apply nodal at v1 and v2 we'll have v1 divided by 30 plus v1 divided by 60 plus 18 equals to 0.
00:38
So this point over here is v1 and this point over here is v2.
00:44
So on solving this we get the value of v1 as equals to minus 360 volt.
00:51
So we get the value of v01 as equals to minus v1 so it will be 360 volt.
00:59
Now for v2 we can write the equation as v2 by 16 plus v2 divided by 40 plus 4 minus 18 equals to 0.
01:12
So from solving this we get the value of v2 as 211 .2 volt.
01:18
So we can write the value of i01 as v2 minus 0 divided by 40 plus 4.
01:26
So on putting the value of v2 as 211 .2 we get the value of i01 as 4 .8 ampere...