For the MnO2 half-reaction:
$$MnO2(s) + 4H^+(aq) + 2e^- \rightarrow Mn^{2+}(aq) + 2H_2O(l) \quad EĀ° = 1.23 V$$
For the Fe3+ half-reaction:
$$Fe^{3+}(aq) + e^- \rightarrow Fe^{2+}(aq) \quad EĀ° = 0.770 V$$
Now, we need to multiply the Fe3+ half-reaction by 2 to
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