00:01
In this problem, we want to figure out a structure, given this information.
00:05
So first, let's find degrees of one saturation.
00:07
So this will tell us the total number of rings and pie bonds.
00:11
So we multiply the number of carbons by two and add two.
00:16
Subtract the number of hydrogens and divide by two.
00:20
So here we get five.
00:23
And typically, we have four or five.
00:27
You have a benzene ring.
00:29
So you have three pie bonds in a ring.
00:31
So that's four degrees and saturn.
00:32
And your ir has this stretch here.
00:35
So this is a carbonyl...