00:01
This is a given equation and this is a given table.
00:05
Now, in this we have to calculate first we have to find the line of equation.
00:16
Line of equation.
00:27
That is y equals to a plus bx here a and b equals to line constant.
00:44
Constant.
00:46
So bx is formulas.
00:53
Here first we have to find a.
00:56
So, summation of x, summation of x square minus summation of x, summation of xy upon n summation of x square minus summation of x whole square.
01:24
Now, put all the values in this formula.
01:31
So we get 421, 20, 5, minus 421, 0, 8, 1, 4 upon upon 9, 20, 3, 1, 5, minus 421 square.
02:00
Again we solve it and we get we get 39, 99, 9, 2, 1 upon 559, 4...