Use the exact values you enter to make later calculations. You monitor the voltage difference across a capacitor in an RC circuit as time passes and find the following results. Time when V = 0 | Time when V = (0.63Vmax) = 6.00 volts 0.040 s | 0.100 s (a) If the equivalent resistance of your circuit is 300.0 ?, calculate the capacitance of the circuit. C = (b) Using this capacitance in your calculation, find the charge on the capacitor when it is fully charged. Q =
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Given: Equivalent resistance (R) = 300.0 Ω Maximum charge on the capacitor (Q) = 6.00 V * 6.00 μF = 36.00 μC Using the formula Q = CV, where Q is the charge, C is the capacitance, and V is the voltage: 36.00 μC = C * 6.00 V C = 36.00 μC / 6.00 V C = 6.00 μF Show more…
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