Question

Use the Factor Theorem to determine whether $x - 3$ is a factor of $P(x) = 2x^4 - 5x^3 - 6x^2 + 27$. Specifically, evaluate $P$ at the proper value, and then determine whether $x - 3$ is a factor. P() = x - 3 is a factor of $P(x)$ x - 3 is not a factor of $P(x)$

          Use the Factor Theorem to determine whether $x - 3$ is a factor of $P(x) = 2x^4 - 5x^3 - 6x^2 + 27$.
Specifically, evaluate $P$ at the proper value, and then determine whether $x - 3$ is a factor.
P() = 
x - 3 is a factor of $P(x)$
x - 3 is not a factor of $P(x)$

Use the Factor Theorem to determine whether x - 3 is a factor of P(x) = 2x^4 - 5x^3 - 6x^2 + 27.
Specifically, evaluate P at the proper value, and then determine whether x - 3 is a factor.
P() =
x - 3 is a factor of P(x)
x - 3 is not a factor of P(x)

Added by Remedios H.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Jenny Van

12/22/2021

Step 1

In this case, $c = 3$, so we need to evaluate $P(3)$. Show more…

Show all steps

Thanks for your feedback!

Use the Factor Theorem to determine whether $x - 3$ is a factor of $P(x) = 2x^4 - 5x^3 - 6x^2 + 27$. Specifically, evaluate $P$ at the proper value, and then determine whether $x - 3$ is a factor. $P(\boxed{ }) = \boxed{ }$ $x - 3$ is a factor of $P(x)$ $x - 3$ is not a factor of $P(x)$