Use the following data to calculate total circulation...

Use the following data to calculate total circulation pressure and ECD flow rate of 450 gpm for: A Newtonian fluid B: Power law fluid n=64 k=300 n=35 C: Bingham fluid Drill Pipe Length - 7,200 ft Drill Pipe OD - 5 in Drill Pipe ID = 4.276 in Drill Collar OD = 7 in. Drill Collar ID = 2.5 in Bit Size = 7 7/8 in. Mud Weight = 12.9 ppg Wellbore Depth Length = 8,000 ft Bit Nozzles = 12-13-13

Transcript

00:01 Here a venturi tube is used to measure the flow rate of gasoline and the radii of inlet and outlet tubes are given and the difference in input and output pressure is also given.

00:20 Using this we have to find the speed of gasoline as it leaves the hose and the fluid flow rate in cubic meters per second.

00:31 So at the inlet the pressure is b1 the cross section area is a1 radius of the cross section is r1 and speed of the fluid is b1 and at the outlet pressure is b2 cross section area is a2 and the radius of the cross section is r2 and speed of the fluid is v2 now we have to find out the speed so for that first we will use equation of continuity according to which a1 v1 is equal to a 2 v2 now area a 1 will be equal to pi r1 square and area a 2 is by r2 square so from this we get v1 equal to r2 square upon r1 square pi cancels out times v2 this can be written as r2 upon r1 now r2 is the radius of the outlet which is 1 .45 centimeter r1 is radius of inlet which is 2 .9 centimeters so from this we get v1 equal to v2 upon 4 this is equation 1 now we will use the bernoulli equation according to which b1 plus half row v1 square row is the density of the fluid plus row g h1 h1 is the height at the outlet sorry at the inlet and at the outlet pressure is b2 half row v2 square and at the outlet the height is h2 so row g h2 but the pipe is horizontal so h1 will be equal to h2 and row g h1 cancels out with row g h2 from this we get b1 minus b2 equal to half row v2 square minus v1 square now v1 is equal to v1 is equal to v2 upon 4 from equation 1 so from for v1 we write b2 upon 4 so this gives us half row v2 square minus v2 square upon 16 which is half row v2 square 1 minus 1 upon 16 now p1 minus p 2 is given which is 1 .2 kilo pascal and kilo pascal is equal to 10 to the power 3 pascal.

04:21 R is the density which is 740 kg per meter cube and v2 is the speed at the outlet which is unknown times 1 minus 1 1 upon 16 so from this we get v2 equal to this is v2 square 1 .86 meter per second so this is the speed at the outlet or of the gasoline as it leaves the hose...

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