Question

Use the following equations to calculate the heat of the reaction for the formation of ethane (C2H6): C2H6(g) + 7/2 O2(g) → 2CO2(g) + 3H2O(l) ∆H° = -1560 kJ C(gr) + O2(g) → CO2(g) ∆H° = -394 kJ H2(g) + 1/2 O2(g) → H2O(l) ∆H° = -286 kJ Calculate ∆H° for the following reaction: 2C(gr) + 3H2(g) → C2H6(g) (ethane) Use kJ for your answer.

          Use the following equations to calculate the heat of the reaction for the formation of ethane (C2H6):

C2H6(g) + 7/2 O2(g) → 2CO2(g) + 3H2O(l)
∆H° = -1560 kJ

C(gr) + O2(g) → CO2(g)
∆H° = -394 kJ

H2(g) + 1/2 O2(g) → H2O(l)
∆H° = -286 kJ

Calculate ∆H° for the following reaction:
2C(gr) + 3H2(g) → C2H6(g) (ethane)

Use kJ for your answer.

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Added by Cameron A.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Susan Hallstrom

11/08/2022

Step 1

Step 1: Write down the given equations and their respective enthalpy values: C2H6(g) + 7/2 O2(g) → 2CO2(g) + 3H2O(l) ΔH° = -1560 kJ C(gr) + O2(g) → CO2(g) ΔH° = -394 kJ H2(g) + 1/2 O2(g) → H2O(l) ΔH° = -286 kJ Show more…

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Use the following equations to calculate the heat of the reaction for the formation of ethane (C2H6): C2H6(g) + 7/2 O2(g) → 2CO2(g) + 3H2O(l) ∆H° = -1560 kJ C(gr) + O2(g) → CO2(g) ∆H° = -394 kJ H2(g) + 1/2 O2(g) → H2O(l) ∆H° = -286 kJ Calculate ∆H° for the following reaction: 2C(gr) + 3H2(g) → C2H6(g) (ethane) Use kJ for your answer.

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Transcript

00:01 We are asked to calculate the enthalpy for the following reaction.

00:05 And i've written this reaction right here.

00:07 This is for the production of ethane.

00:11 My equations are 2 co2 and what's my water here? 3h2o.

00:42 My enthalpye of reaction for this one is negative 1560 kilojoules.

00:55 Second reaction, c.

01:00 And this should be graphite, not g.

01:03 Graphite plus o2 yields co2.

01:14 My delta h for this reaction is negative 394 kilojoules.

01:24 And i hope i only have three here, 394.

01:27 Next we have h2 plus one half o2.

01:32 Both of these are gas.

01:36 And my product of course will be water, h2o.

01:40 And that's h2ol.

01:43 I delta h2 for this is is negative 286.

01:52 So we're going to rearrange our equation so everything cancels out.

01:57 Let's do that in red.

01:59 First for this reaction, i'm going to flip this reaction, or reverse this reaction, i should say.

02:06 And if i reverse this reaction, let me get that written down.

02:12 I've got 2 -c -o -2 plus 3h -2o, and that will yield c -2 -2 -2.

02:26 H6g plus 7 over 2 .02g.

02:32 And that means i will also flip my signs.

02:36 That'll be positive 1560 kilojoules.

02:42 Next, i need my h2 on this side, so that one's going to stay...

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