00:01
So here we're given that the number of decibels, beta, can be described as 10 times log of the intensity over our reference intensity, which is 10 to the power negative 12.
00:23
Here we want to find for each of these.
00:27
So they're all expressed in powers of 10.
00:30
So let's just say if we can express i as a power of 10, what would beta be would be beta equals 10 times log? if this is 10 to the a over 10 to the minus 12, this is 10 times log of 10 to the a minus 12, which is a minus 12 times 10 times log of 10, which is just 1.
00:55
So for part a, our power of 10 is negative 4.
01:07
And so if we have negative 4, that would be 10 to the minus 16, which would be minus 10 times log of 10 to the minus 16.
01:33
Oh, excuse me, plus 12.
01:35
There's our error...