Use the following reactions to find ΔH when 1 mole of HCl gas forms from its elements: N2 (g) + 3 H2 (g) ⟶ 2 NH3 (g) ΔH = -91.8 kJ N2 (g) + 4 H2(g) + Cl2(g) ⟶ 2 NH4Cl(s) ΔH = -628.8 kJ NH3 (g) + HCl(g) ⟶ NH4Cl(s) ΔH = -176.2 kJ
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Step 1
The reaction is: H2 (g) + Cl2 (g) ⟶ 2 HCl (g) Now, we need to manipulate the given reactions to get this reaction. From the first reaction, we can get H2 (g) by reversing the reaction and dividing by 3: 2 NH3 (g) ⟶ N2 (g) + 3 H2 (g) ΔH = 91.8 kJ Show more…
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