00:01
In this problem we are looking at using the frequency distribution below which is given here, which is not adequately provided because it says the class interval is non -continuous.
00:11
As you can see, it's going between 20 to 30, 31 to 41.
00:15
So there is a relatively discrete amount of class interval that's going on here.
00:20
Frequency appears to be complete but the class interval needs modification and it has to be existing data, we have to modify the class interval so the class interval is complete in the first place.
00:34
So how do you modify a class interval that is non -continuous? by making it continuous by adding 0 .5 on each side so if you look at this class interval that's given here in the problem so that's written out here as 20 to 30 30 31 to 41, 42 to 50 to 63 so if you make it continuous by adding point five subtracting 0 .5 on the left and adding point 5 on the right you would get this continuous distribution of class interval and then preserving the existing data of class interval then is given.
01:08
So that's very important.
01:10
Modifying a class interval would also mean preserving the existing class interval.
01:15
The midpoint of the class interval, which is also asked here, as you can see, one of the asking points was the class frequency, modification...