00:01
We're being asked to use point slope form to write the equation of a line that goes through the point negative 2, negative 2, and is perpendicular to the line y equals 1 3 3rd x minus 5.
00:09
Well, remember, point slope form is y minus y sub 1 equals m times x minus x of 1.
00:16
So in order to use point slope form, we need the point on the line, which we have, negative 2, negative 2, so negative 2 is our x of 1, and negative 2 is also our y sub 1.
00:26
But m is our slope, which we don't have.
00:29
However, we know that our line is perpendicular to this line y equals 1 3rd x minus 5.
00:35
Remember, perpendicular lines have slopes that are opposite reciprocals.
00:40
So the slope of the given line is 1 third.
00:42
So the slope of our line will be the opposite reciprocal.
00:46
So the opposite sign, so it will be negative, and the reciprocal of 1 third, which is 3 over 1, or just 3.
00:53
So now that we know the slope of our line and the point, we can now use point slope form.
00:58
So let's substitute these values in...