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Use the Law of Sines to solve for all possible triangles that satisfy a=45,c=24(,)/(_(A))= 123deg conditions. /_(B)=30deg (,)/(_(C))=27deg ,b=33 /_(B)=27deg (,)/(_(C))=30deg ,b=31 /_(B)=30deg (,)/(_(C))=27deg ,b=27 /_(B)=32deg (,)/(_(C))=26deg ,b=26 Use the Law of Sines to solve for all possible triangles that satisfy a = 45, c = 24, A = 123'conditions. B=30C=27b=33 OB=27C=30b=31 B=30C=27.b=27 B=32.C=26.b=26

Name: use the law of sines to solve for all possible triangles that satisfy a45c24a 123deg conditions b30deg c27deg b33 b27deg c30deg b31 b30deg c27deg b27 b32deg c26deg b26 use the law o 45556
Uploaded: 2022-06-17T08:03:36-08:00
Duration: 4 min 45 s
Channel: Sri K
Description: use the law of sines to solve for all possible triangles that satisfy a45c24a 123deg conditions b30deg c27deg b33 b27deg c30deg b31 b30deg c27deg b27 b32deg c26deg b26 use the law o 45556

          Use the Law of Sines to solve for all possible triangles that satisfy a=45,c=24(,)/(_(A))= 123deg  conditions.
/_(B)=30deg (,)/(_(C))=27deg ,b=33
/_(B)=27deg (,)/(_(C))=30deg ,b=31
/_(B)=30deg (,)/(_(C))=27deg ,b=27
/_(B)=32deg (,)/(_(C))=26deg ,b=26
Use the Law of Sines to solve for all possible triangles that satisfy a = 45, c = 24, A = 123'conditions.
B=30C=27b=33
OB=27C=30b=31
B=30C=27.b=27
B=32.C=26.b=26

use the law of sines to solve for all possible triangles that satisfy a45c24a 123deg conditions b30deg c27deg b33 b27deg c30deg b31 b30deg c27deg b27 b32deg c26deg b26 use the law o 45556

Added by Amanda P.

Precalculus with Limits

Ron Larson 2nd Edition

Instant Answer

Solved by Expert Sri K

06/17/2022

Step 1

sin(A)/a = sin(B)/b = sin(C)/c sin(123°)/45 = sin(30°)/b = sin(27°)/24 b = (sin(30°) * 45) / sin(123°) b ≈ 31.02 Step 2: Use the Law of Sines to find side b in the triangle where A = 123°, B = 27°, and C = 30°. sin(A)/a = sin(B)/b = sin(C)/c Show more…

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Use the Law of Sines to solve for all possible triangles that satisfy a=45,c=24(,)/(_(A))= 123deg conditions. /_(B)=30deg (,)/(_(C))=27deg ,b=33 /_(B)=27deg (,)/(_(C))=30deg ,b=31 /_(B)=30deg (,)/(_(C))=27deg ,b=27 /_(B)=32deg (,)/(_(C))=26deg ,b=26 Use the Law of Sines to solve for all possible triangles that satisfy a = 45, c = 24, A = 123'conditions. B=30C=27b=33 OB=27C=30b=31 B=30C=27.b=27 B=32.C=26.b=26