Question

Use the product property of logarithms to write the logarithm as a sum of logarithms. Then simplify if possible. $\log_{\frac{1}{2}}(abc)$ Select one: a. $\frac{1}{2}\log\ a + \frac{1}{2}\log\ b + \frac{1}{2}\log\ c$ b. $\log_{\frac{1}{2}}a + \log_{\frac{1}{2}}b + \log_{\frac{1}{2}}c$ c. $(\log_{\frac{1}{2}}a)(\log_{\frac{1}{2}}b)(\log_{\frac{1}{2}}c)$ d. $\log_{\frac{1}{2}}a - \log_{\frac{1}{2}}b - \log_{\frac{1}{2}}c$

          Use the product property of logarithms to write the logarithm as a sum of logarithms. Then simplify if possible.
$\log_{\frac{1}{2}}(abc)$
Select one:
a. $\frac{1}{2}\log\ a + \frac{1}{2}\log\ b + \frac{1}{2}\log\ c$
b. $\log_{\frac{1}{2}}a + \log_{\frac{1}{2}}b + \log_{\frac{1}{2}}c$
c. $(\log_{\frac{1}{2}}a)(\log_{\frac{1}{2}}b)(\log_{\frac{1}{2}}c)$
d. $\log_{\frac{1}{2}}a - \log_{\frac{1}{2}}b - \log_{\frac{1}{2}}c$

Use the product property of logarithms to write the logarithm as a sum of logarithms. Then simplify if possible.
log(1)/(2)(abc)
Select one:
a. (1)/(2)log a + (1)/(2)log b + (1)/(2)log c
b. log(1)/(2)a + log(1)/(2)b + log(1)/(2)c
c. (log(1)/(2)a)(log(1)/(2)b)(log(1)/(2)c)
d. log(1)/(2)a - log(1)/(2)b - log(1)/(2)c

Added by Janice W.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Subhadeepta Sahoo

08/11/2021

Step 1

The product property of logarithms states that log_b(mn) = log_b(m) + log_b(n). We can apply this property to the given logarithm by treating abc as the product of a, b, and c. Show more…

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Use the product property of logarithms to write the logarithm as a sum of logarithms. Then simplify if possible. log_((1)/(2))(abc) Select one: a. (1)/(2)loga+(1)/(2)logb+(1)/(2)logc b. log_((1)/(2))a+log_((1)/(2))b+log_((1)/(2))c c. (log_((1)/(2))a)(log_((1)/(2))b)(log_((1)/(2))c) d. log_((1)/(2))a-log_((1)/(2))b-log_((1)/(2))c Use the product property of logarithms to write the logarithm as a sum of logarithms. Then simplify if possible. log1,(abc) Select one: O a. J log a + log b + log c O b. logu, a+ logu, b + logn, c O c.(logy, a)(log, b)(log, c) O d. logy, a - logi, b - logi, c