Use the product-to-sum identities to rewrite the following expression as a sum or difference. $3\sin(x + y)\cos(x + y)$
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Step 1
The product-to-sum identity for $\sin A \cos B$ is: $\sin A \cos B = \frac{1}{2}[\sin(A + B) + \sin(A - B)]$ In our given expression, we have $3\sin(x + y)\cos(x + y)$. Let $A = x + y$ and $B = x + y$. Step 2: Apply the product-to-sum identity. Substitute $A = Show more…
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