Use the quadratic formula to solve the equation. $$z^2 + 12z + 26 = 0$$ A. $$-12 + \sqrt{26}$$ B. $$6 \pm \sqrt{26}$$ C. $$6 + \sqrt{10}$$ D. $$-6 \pm \sqrt{10}$$
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We need to solve this equation using the quadratic formula. The quadratic formula for an equation of the form $ax^2 + bx + c = 0$ is given by: $$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$ Step 2: In our equation, $z^2 + 12z + 26 = 0$, we have: $a = 1$ $b = 12$ $c = Show more…
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