According to the following reaction, how many moles of mercury(II) oxide are necessary to form 0.263 moles oxygen gas? mercury(II) oxide (s) ? mercury (l) + oxygen (g) moles mercury(II) oxide
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First, we need to write the balanced chemical equation for the reaction: 2HgO -> 2Hg + O2 This tells us that for every 2 moles of mercury(II) oxide (HgO) that react, we get 1 mole of oxygen gas (O2) produced. Show more…
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According to the following reaction, how many grams of mercury(II) oxide are needed to form 26.2 grams of oxygen gas? Mercury(II) oxide (s) → Mercury (l) + Oxygen (g)
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