Use the References to access important values if needed for...

Use the References to access important values if needed for this question. A sample of gas contains 0.1792 mol of CO(g) and 0.08960 mol of O$_2$(g) and occupies a volume of 11.8 L. The following reaction takes place: 2CO(g) + O$_2$(g) $\rightarrow$ 2CO$_2$(g) Calculate the volume of the sample after the reaction takes place, assuming that the temperature and the pressure remain constant and the reaction goes to the completion. Volume = L

Transcript

00:01 Hello student in this question a equation is given that is 4 of nh3 in gaseous state is reacting with 5 of o2 in gaseous state is giving to 4 of no that means in gas plus 6h2o which is again in gas.

00:23 Now, the moles of moles of nh3 is equal to 0 .11 mole and that of o2 is equal to 0 .1375 mole.

00:41 And the initial volume of the container, so volume which is initial, so we are abbreviating is v1 is equal to 15 liter.

00:54 Now, moles of reactants, so moles of reactant, that means n1 is equal to moles of nh3 plus moles of oxygen.

01:10 So it will be equal to 0 .11 plus 0 .1375.

01:16 That is equal to 0 .2475 moles.

01:22 As can be seen in the reaction, 4 moles of nh3 result in the formation of 4 moles of no.

01:37 So it can be said that the number of no formed will be same.

01:42 So we can write down 1 mole of no will be equal to 1 mole of nh3, 4 mole of nh3, 4.

01:53 So here the moles of the moles of no will be 0 .11 moles.

02:04 So now we can say that 4 moles of nh3 result in the formation of 6 moles of h2o.

02:19 So it can be said that 6 moles of h2o.

02:25 Is equal to 4 moles of nh3.

02:30 So here, 1 .5 moles of h2o will be equal to 1 mole of nh3.

02:43 So it implies that moles of h2o, moles of h2o is 1 .5 multiplied by 0 .1 .1.

02:58 Is equal to 0 .165 moles.

03:05 Now, moles of product, moles of product, that means the n2 is equal to moles of h2o plus moles of no.

03:17 So, it will be 0 .11 plus 0 .165, that is equal to 0 .275.

03:26 Now we have n1, n2 and v1, we have to find out the v2 value, that means the final volume.

03:35 So we can write down according to the universal gas constant law, pv is equal to nrt.

03:43 We know this.

03:44 So from here we can write down p v1 is equal to n1rt and pv2 is equal to n2rt.

03:59 Now, from there, we can be say that n1 divided by v1 is equal to n2 divided by v2.

04:09 And we have to find out the volume of v2...

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