00:01
Okay, so in this question we're asked to find all values of k that satisfy this equation.
00:08
So let's just simplify it, right? let's start with the second bit, 1, 1, 0, 1, 0, 2, 0, 2 minus 3 times k, 1, 1.
00:19
This gives us the vector as a column, 1 times k plus 1 plus 0, k plus 1, so it's this row times the column.
00:29
Second row times the column, we get k plus 2.
00:33
Last row times the column, we get 2 minus 3, that's minus 1...