00:01
Hello, in this question we are given the solubility curves for the selected solutes.
00:07
So now for the first one, we have given that is the kcl at 80 degree celsius.
00:19
So from the solubility curve we need to find out the grams here, grams of those solid.
00:24
Solute it is.
00:25
So as we can see here in this case, this kcl at 80 degree celsius.
00:32
So as you can see from the graph this point it lies somewhere here.
00:37
So therefore from the graph from the solubility curve we can say that it is 52 grams.
00:48
Next we have that is the kc lo3 at 90 degrees celsius.
01:01
So from the graph we can see here that kc lo3 at 90 degrees celsius.
01:10
Intersecting somewhere here so this is nothing but it goes to the 50 so therefore the mass where here it will be 50 grams next we have that is nano3 at 10 degrees celsius so therefore nano3 at 10 degrees celsius so the value will be it lies here so therefore the mass will be 80 grams.
01:44
Next we have that is so2 at 20 degrees celsius.
01:53
Now let us see so2 at 20 degrees celsius so the value will lie here.
01:59
So approximately 10 grams we can say that 10 grams it is there according to the graph.
02:07
In the next one we have nh4 cl...