Question

Use the t-distribution to find a confidence interval for a difference in means $\mu_1 - \mu_2$ given the relevant sample results. Give the best estimate for $\mu_1 - \mu_2$, the margin of error, and the confidence interval. Assume the results come from random samples from populations that are approximately normally distributed. A 90% confidence interval for $\mu_1 - \mu_2$ using the sample results $\bar{x}_1 = 540, s_1 = 140, n_1 = 320$ and $\bar{x}_2 = 457, s_2 = 89, n_2 = 200$ Enter the exact answer for the best estimate and round your answers for the margin of error and the confidence interval to two decimal places. Best estimate = 83 Margin of error = 16.52 Confidence interval: 66.48 to 99.52

          Use the t-distribution to find a confidence interval for a difference in means $\mu_1 - \mu_2$ given the relevant sample results. Give the best estimate for $\mu_1 - \mu_2$, the margin of error, and the confidence interval. Assume the results come from random samples from populations that are approximately normally distributed.
A 90% confidence interval for $\mu_1 - \mu_2$ using the sample results $\bar{x}_1 = 540, s_1 = 140, n_1 = 320$ and $\bar{x}_2 = 457, s_2 = 89, n_2 = 200$
Enter the exact answer for the best estimate and round your answers for the margin of error and the confidence interval to two decimal places.
Best estimate = 83
Margin of error = 16.52
Confidence interval: 66.48 to 99.52

$Use the t-distribution to find a confidence interval for a difference in means μ1 - μ2 given the relevant sample results. Give the best estimate for μ1 - μ2, the margin of error, and the confidence interval. Assume the results come from random samples from populations that are approximately normally distributed. A 90% confidence interval for $\mu1 - \mu2$ using the sample results $\bar{x}1 = 540, s1 = 140, n1 = 320$ and $\bar{x}2 = 457, s2 = 89, n2 = 200$ Enter the exact answer for the best estimate and round your answers for the margin of error and the confidence interval to two decimal places. Best estimate = 83 Margin of error = 16.52 Confidence interval: 66.48 to 99.52$

Added by Rachel B.

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