Use the thermochemical equations shown below to determine the enthalpy for the reaction: C2H6O(l)+3O2(g)-> 2CO2(g)+3H2O(l) 2C2H4O(l)+2H2O(l) -> 2C2H6O(l)+O2(g) ΔH°= +203.5kJ 2CO2 (g)+2H2O(l) -> C2H4O(l)+5/2O2(g) ΔH°= +583.5kJ
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5 kJ/2 = -291.75 kJ. ** Show more…
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