Question

Use this drawing for the questions on this page. We will ignore friction forces with the vertical wall. 10) If she weighs 500 N, which is the correct torque equation, taking torques around her feet, to calculate the force, F, that the wall exerts to keep her standing? a. (500 N)(1.10 m)(sin 30) - F(1.50 m)(sin 60) = 0 b. (500 N)(1.10 m)(sin 60) - F(1.50 m)(sin 60) = 0 c. (500 N)(1.10 m)(sin 30) - F(1.50 m)(sin 30) = 0 d. (500 N)(1.50 m)(sin 30) - F(1.50 m)(sin 60) = 0 11) What can you say about the friction force (f) required to keep her from sliding? It is equal to a. her weight. b. the force from the wall on her shoulders, F. c. her weight divided by the force F. d. F divided by her weight. 12) What can you say about the normal force, that is, the force of the floor pushing up on her feet? It is equal to a. her weight. b. the force from the wall on her shoulders, F. c. her weight divided by the force F. d. F divided by her weight. 13) What can you say about the coefficient of friction (?) required to keep her from sliding? It is equal to a. her weight. b. the force from the wall on her shoulders, F. c. her weight divided by the force F. d. F divided by her weight. 14) What would happen if you took torques around another point, say, her center of gravity? a. I would get entirely different answers. b. I would get the same answers with the same amount of effort. c. I would get the same answers, but with much more effort, because the torque equation would have several unknowns.

          Use this drawing for the questions on this page.
We will ignore friction forces with the vertical wall.

10) If she weighs 500 N, which is the correct torque equation, taking torques around her feet, to calculate the force, F, that the wall exerts to keep her standing?
a. (500 N)(1.10 m)(sin 30) - F(1.50 m)(sin 60) = 0
b. (500 N)(1.10 m)(sin 60) - F(1.50 m)(sin 60) = 0
c. (500 N)(1.10 m)(sin 30) - F(1.50 m)(sin 30) = 0
d. (500 N)(1.50 m)(sin 30) - F(1.50 m)(sin 60) = 0

11) What can you say about the friction force (f) required to keep her from sliding? It is equal to
a. her weight.
b. the force from the wall on her shoulders, F.
c. her weight divided by the force F.
d. F divided by her weight.

12) What can you say about the normal force, that is, the force of the floor pushing up on her feet? It is equal to
a. her weight.
b. the force from the wall on her shoulders, F.
c. her weight divided by the force F.
d. F divided by her weight.

13) What can you say about the coefficient of friction (?) required to keep her from sliding?
It is equal to
a. her weight.
b. the force from the wall on her shoulders, F.
c. her weight divided by the force F.
d. F divided by her weight.

14) What would happen if you took torques around another point, say, her center of gravity?
a. I would get entirely different answers.
b. I would get the same answers with the same amount of effort.
c. I would get the same answers, but with much more effort, because the torque equation would have several unknowns.

Use this drawing for the questions on this page.
We will ignore friction forces with the vertical wall.

10) If she weighs 500 N, which is the correct torque equation, taking torques around her feet, to calculate the force, F, that the wall exerts to keep her standing?
a. (500 N)(1.10 m)(sin 30) - F(1.50 m)(sin 60) = 0
b. (500 N)(1.10 m)(sin 60) - F(1.50 m)(sin 60) = 0
c. (500 N)(1.10 m)(sin 30) - F(1.50 m)(sin 30) = 0
d. (500 N)(1.50 m)(sin 30) - F(1.50 m)(sin 60) = 0

11) What can you say about the friction force (f) required to keep her from sliding? It is equal to
a. her weight.
b. the force from the wall on her shoulders, F.
c. her weight divided by the force F.
d. F divided by her weight.

12) What can you say about the normal force, that is, the force of the floor pushing up on her feet? It is equal to
a. her weight.
b. the force from the wall on her shoulders, F.
c. her weight divided by the force F.
d. F divided by her weight.

13) What can you say about the coefficient of friction (?) required to keep her from sliding?
It is equal to
a. her weight.
b. the force from the wall on her shoulders, F.
c. her weight divided by the force F.
d. F divided by her weight.

14) What would happen if you took torques around another point, say, her center of gravity?
a. I would get entirely different answers.
b. I would get the same answers with the same amount of effort.
c. I would get the same answers, but with much more effort, because the torque equation would have several unknowns.

Added by Alvaro M.

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