Use your calculator to graph the following functions. f(x) = tan(x + π) f(x) = tan(x) a. What do you notice about the graphs of these two functions? b. Observe the period for f(x) = tan(x + π) and f(x) = tan(x). Then, compare and contrast the period of f(x) = tan(x + π) and f(x) = tan(x).
Added by Kimberly H.
Step 1
** Show more…
Show all steps
Close
Your feedback will help us improve your experience
James Kiss and 58 other Precalculus educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Consider the following functions ( $a$ )- ( $f$ ). Without graphing them, answer question. a) $f(x)=2 \sin \left(\frac{1}{2} x-\frac{\pi}{2}\right)$ b) $f(x)=\frac{1}{2} \cos \left(2 x-\frac{\pi}{4}\right)+2$ c) $f(x)=-\sin \left[2\left(x-\frac{\pi}{2}\right)\right]+2$ d $f(x)=\sin (x+\pi)-\frac{1}{2}$ e) $f(x)=-2 \cos (4 x-\pi)$ f) $(x)=-\cos \left[2\left(x-\frac{\pi}{8}\right)\right]$ Which functions have a graph with a period of $\pi ?$
Trigonometric Identities, Inverse Functions, and Equations
Identities: Cofunction, Double-Angle, and Half-Angle
Consider the following functions ( $a$ ) $-(f) .$ Without graphing them, answer questions. a) $f(x)=2 \sin \left(\frac{1}{2} x-\frac{\pi}{2}\right)$ b) $f(x)=\frac{1}{2} \cos \left(2 x-\frac{\pi}{4}\right)+2$ c) $f(x)=-\sin \left[2\left(x-\frac{\pi}{2}\right)\right]+2$ d) $f(x)=\sin (x+\pi)-\frac{1}{2}$ e) $f(x)=-2 \cos (4 x-\pi)$ f) $f(x)=-\cos \left[2\left(x-\frac{\pi}{8}\right)\right]$ Which functions have a graph with a period of $2 \pi ?$
Recommended Textbooks
Precalculus with Limits
Precalculus
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD