00:01
In this question, we are assigned to the task to predict the electronic configuration of each ion.
00:10
In the part a of the question, we have cs2 positive.
00:16
The atomic number for cesium is 55.
00:20
Therefore, the electronic configuration is 1 s2, 2 is 2, 2p 6, 3 s2, 3p6.
00:30
4 s2 3d10 4p 6 5 s2 4d10 and 5p 7 now in ch2 positive there are 2 electrons are removed with results in the formation of ccm2 positive therefore it should be 5p 5 this is the electronic configuration for czcm 2 positive in the 5 p of the question we have bismet 2 positive.
01:09
The atomic number for bismuth is 83 which suggests that it has 83 electron.
01:15
After removing 2 electrons is from bismuth 2 positive and the number of electron is 81.
01:22
Therefore the electronic configuration is 1 , 2 , 2 , 3 , 3p6, 4 .h2, 3d10, 4p6, 5f2, 4d10, 5p6, 5d10, 4f40 and 6p3.
01:48
This is the electronic configuration for bismuth 2 positive.
01:54
Now in the c part of the question, we have to write the electronic configuration for k positive...