using enthalpies of formation calculate h for the following reaction at 25c also calculate s for

Name: using enthalpies of formation calculate h for the following reaction at 25c also calculate s for the reaction from standard enthalpies at 25c use these values to calculate g for the reaction at this t
Uploaded: 2022-07-05T13:13:42-08:00
Duration: 5 min 4 s
Channel: Suman K
Description: using enthalpies of formation calculate h for the following reaction at 25c also calculate s for the reaction from standard enthalpies at 25c use these values to calculate g for the reaction at this t

First, we need to calculate ΔH° for the reaction. We can do this using the enthalpies of formati

Question

Using enthalpies of formation, calculate ΔH° for the following reaction at 25°C. Also calculate ΔS° for the reaction from standard enthalpies at 25°C. Use these values to calculate ΔG° for the reaction at this temperature. Express your answer to two decimal places COCl2(g) ----> CO(g) + Cl2(g) ΔHf°(COCl2(g)) = -218.8 kJ/mol Sf°(COCl2(g)) = 283.53 J/(K·mol) ΔHf°(CO(g)) = -110.52 kJ/mol Sf°(CO(g)) = 197.67 J/(K·mol) ΔHf°(Cl2(g)) = 0 kJ/mol Sf°(Cl2(g)) = 223.07 J/(K·mol)

          Using enthalpies of formation, calculate ΔH° for the following reaction at 25°C. Also calculate ΔS° for the reaction from standard enthalpies at 25°C. Use these values to calculate ΔG° for the reaction at this temperature. Express your answer to two decimal places

COCl2(g) ----> CO(g) + Cl2(g)

 

ΔHf°(COCl2(g)) = -218.8 kJ/mol          Sf°(COCl2(g)) = 283.53 J/(K·mol) 

ΔHf°(CO(g)) = -110.52 kJ/mol            Sf°(CO(g)) = 197.67 J/(K·mol) 

ΔHf°(Cl2(g)) = 0 kJ/mol                     Sf°(Cl2(g)) = 223.07 J/(K·mol)

Added by Sarah S.

Chemistry

Raymond Chang, Kenneth A. Goldsby 12th Edition

Chapter 20

Instant Answer

Solved by Expert Suman K

07/05/2022

Step 1

We can do this using the enthalpies of formation (ΔHf°) of the reactants and products: ΔH° = Σ ΔHf°(products) - Σ ΔHf°(reactants) ΔH° = [ΔHf°(CO(g)) + ΔHf°(Cl2(g))] - ΔHf°(COCl2(g)) ΔH° = [(-110.52 kJ/mol) + (0 kJ/mol)] - (-218.8 kJ/mol) ΔH° = 108.28 kJ/mol Show more…

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Using enthalpies of formation, calculate ΔH° for the following reaction at 25°C. Also calculate ΔS° for the reaction from standard enthalpies at 25°C. Use these values to calculate ΔG° for the reaction at this temperature. Express your answer to two decimal places COCl2(g) ----> CO(g) + Cl2(g) ΔHf°(COCl2(g)) = -218.8 kJ/mol Sf°(COCl2(g)) = 283.53 J/(K·mol) ΔHf°(CO(g)) = -110.52 kJ/mol Sf°(CO(g)) = 197.67 J/(K·mol) ΔHf°(Cl2(g)) = 0 kJ/mol Sf°(Cl2(g)) = 223.07 J/(K·mol)