Using the compound interest formula, how much would you need to invest at 6.5% interest to have $20,000 in 6 years, compounded monthly? Round your answer to the nearest cent, if needed. A) $29,508.54 B) $13,718.55 C) $73,771.36 D) $13,555.40
Added by Ana M.
Step 1
5% = 0.065 (as a decimal) n = 12 (since the interest is compounded monthly) t = 6 years We can rearrange the formula to solve for P: P = A / (1 + r/n)^(nt) Substituting the values we know: P = $20,000 / (1 + 0.065/12)^(12*6) P = $13,718.55 Show more…
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$$ \begin{array}{l}{\text { Compound Interest A woman invests } \$ 6500 \text { in an account }} \\ {\text { that pays } 6 \% \text { interest per year, compounded continuously. }} \\ {\text { (a) What is the amount after } 2 \text { years? }} \\ {\text { (b) How long will it take for the amount to be } \$ 8000 ?}\end{array} $$
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\begin{equation} \begin{array}{l}{\text { Compound Interest } \text { A woman invests } \$ 6500 \text { in an account }} \\ {\text { that pays } 6 \% \text { interest per year, compounded continuously. }} \\ {\text { (a) What is the amount after } 2 \text { years? }} \\ {\text { (b) How long will it take for the amount to be } \$ 8000 ?}\end{array} \end{equation}
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