00:01
Hello student we are provided with the reaction.
00:03
Okay so the reaction is a plus 2b giving c plus b okay so now we have to find out the order of the reactants in terms of a and b also.
00:22
Okay so we have to find out the rate with respect to the concentration of a and concentration of b that is let's say a to the power n and b to the power m.
00:32
So the total order of the reaction will be n plus m.
00:37
We have to find out n and m.
00:39
And we are provided with a table also.
00:42
Okay, so from using that table, we can find or we can have different equations.
00:47
Okay.
00:48
So using the first row in the table, we can make rate 1, that is r1 is equal to rate is given as 0 .01 .077 mole per second.
01:02
Okay, 7 -7.
01:05
Then, which is equal to, we can write like this, the rate of a reaction can be expressed as rate is equal to rate constant k into concentration of the reactant to the power n into concentration of the reactant b to the power m.
01:22
Okay, so here r1 is equal to 0 .01777 is equal to a to the power.
01:29
Here the concentration of a is given, that is, k into 0 .4 .00 to the power n into concentration of b is given 0 .390 to the power m.
01:45
Okay.
01:46
So r2 is equal to 0 .177 is equal to k into 0 .4 .00 to the power n into 0 .780 to the power m.
02:02
Okay...