Question

Using the equation shown below: 2Mg(s) + O2(g) -> 2MgO(s). When 10.1 g of Mg reacts with 10.5 g of O2, 11.9 g of MgO is collected. Determine the limiting reactant, excess reactant, theoretical yield, and percent yield for the product of this reaction. Also calculate the remaining excess reactant from the reaction.

          Using the equation shown below: 2Mg(s) + O2(g) -> 2MgO(s). When 10.1 g of Mg reacts with 10.5 g of O2, 11.9 g of MgO is collected. Determine the limiting reactant, excess reactant, theoretical yield, and percent yield for the product of this reaction. Also calculate the remaining excess reactant from the reaction.
        
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Chemistry: Structure and Properties
Chemistry: Structure and Properties
Nivaldo Tro 2nd Edition
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Using the equation shown below: 2Mg(s) + O2(g) -> 2MgO(s). When 10.1 g of Mg reacts with 10.5 g of O2, 11.9 g of MgO is collected. Determine the limiting reactant, excess reactant, theoretical yield, and percent yield for the product of this reaction. Also calculate the remaining excess reactant from the reaction.
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Magnesium oxide can be made by heating magnesium metal in the presence of oxygen. The balanced equation for the reaction is: 2Mg(s)+O2(g)→2MgO(s) When 10.1 g of Mg are allowed to react with 10.5 g of O2, 11.8 g of MgO are collected. Determine the limiting reactant for the reaction. Express your answer as a chemical formula. Determine the theoretical yield for the reaction. Determine percent yield for the reaction.

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Magnesium oxide can be produced by heating magnesium metal in the presence of oxygen. The balanced equation for the reaction is: $$2 \mathrm{Mg}(s)+\mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{MgO}(s)$$ When $10.1 \mathrm{g}$ of $\mathrm{Mg}$ react with $10.5 \mathrm{g}$ of $\mathrm{O}_{2}, 11.9 \mathrm{g}$ of $\mathrm{MgO}$ are collected. Determine the limiting reactant, theoretical yield, and percent yield for the reaction.

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Transcript

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00:01 First, we'll rewrite the balanced chemical reaction.
00:06 Two magnesiums react with oxygen to produce two magnesium oxides.
00:14 If we have 10 .1 grams of magnesium, we can calculate the amount of magnesium oxide that would be produced if all of it is consumed.
00:23 We divide by the molar mass of magnesium to get moles, and then convert the moles magnesium to moles magnesium oxide with the 2 to 2 mole relationship.
00:35 Once we know moles magnesium oxide, we multiply by the molar mass magnesium oxide to get grams.
00:43 We do a similar calculation with the 10 .5 grams oxygen, converting it to moles oxygen, dividing by the molar mass o2, then converting moles o2 to moles mgo with a 1 to 2 mole relationship.
00:58 And then last of all, multiply by the molar mass magnesium oxide.
01:02 So if all the magnesium is consumed, would get 6 ,000.
01:06 16 .7 grams magnesium oxide...
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