00:01
In this problem, we're told that we have a molecular formula that's c7h9n.
00:08
So first, let's find degrees of unsaturation.
00:12
This is going to tell us the number of rings and pie bonds, and this will help us to ultimately draw out our structure given nmr data.
00:24
So we multiply the number of carbons by 2 and add 2, subtract the number of hydrogens, add the number of nitrogen and divide by two.
00:35
So we have 16 minus 8 over 2, so we get 4.
00:43
So typically when you see 4 degrees of unsaturation, that's going to mean that you have a benzene ring because you have three pi bonds and one ring to give 4 degrees of unsaturation.
00:54
And this is supported by your nmr data.
00:57
So you have five hydrogens in the 7 to 8 part per million range, these are going to be your aromatic hydrogens.
01:07
So this tells us that you have a mono -substituted ring because you have five hydrogens.
01:15
And then you have two hydrogens that are around four...