Using the standard enthalpies of formation, determine the standard enthalpy of the following reaction: CH4(g) + 2Cl2(g) → CH2Cl2(l) + 2HCl(g), ΔH°rxn = ? kJ ΔH°f / (kJ/mol) CH4(g) -75 CH2Cl2(l) -124 HCl(g) -92
Added by Shane K.
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Step 1:** Calculate the standard enthalpy change for the formation of CH2Cl2(l): ΔH°f = -124 kJ/mol ** Show more…
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